Optimal. Leaf size=171 \[ -\frac {a^2 \left (2 A (c-2 d) d-B \left (2 c^2-4 c d+3 d^2\right )\right ) x}{2 d^3}-\frac {2 a^2 (c-d)^2 (B c-A d) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{d^3 \sqrt {c^2-d^2} f}+\frac {a^2 (2 B c-2 A d-3 B d) \cos (e+f x)}{2 d^2 f}-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f} \]
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Rubi [A]
time = 0.35, antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 7, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {3055, 3047,
3102, 2814, 2739, 632, 210} \begin {gather*} -\frac {2 a^2 (c-d)^2 (B c-A d) \text {ArcTan}\left (\frac {c \tan \left (\frac {1}{2} (e+f x)\right )+d}{\sqrt {c^2-d^2}}\right )}{d^3 f \sqrt {c^2-d^2}}-\frac {a^2 x \left (2 A d (c-2 d)-B \left (2 c^2-4 c d+3 d^2\right )\right )}{2 d^3}+\frac {a^2 (-2 A d+2 B c-3 B d) \cos (e+f x)}{2 d^2 f}-\frac {B \cos (e+f x) \left (a^2 \sin (e+f x)+a^2\right )}{2 d f} \end {gather*}
Antiderivative was successfully verified.
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rule 3047
Rule 3055
Rule 3102
Rubi steps
\begin {align*} \int \frac {(a+a \sin (e+f x))^2 (A+B \sin (e+f x))}{c+d \sin (e+f x)} \, dx &=-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f}+\frac {\int \frac {(a+a \sin (e+f x)) (a (B c+2 A d)-a (2 B c-2 A d-3 B d) \sin (e+f x))}{c+d \sin (e+f x)} \, dx}{2 d}\\ &=-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f}+\frac {\int \frac {a^2 (B c+2 A d)+\left (a^2 (B c+2 A d)-a^2 (2 B c-2 A d-3 B d)\right ) \sin (e+f x)-a^2 (2 B c-2 A d-3 B d) \sin ^2(e+f x)}{c+d \sin (e+f x)} \, dx}{2 d}\\ &=\frac {a^2 (2 B c-2 A d-3 B d) \cos (e+f x)}{2 d^2 f}-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f}+\frac {\int \frac {a^2 d (B c+2 A d)-a^2 \left (2 A (c-2 d) d-B \left (2 c^2-4 c d+3 d^2\right )\right ) \sin (e+f x)}{c+d \sin (e+f x)} \, dx}{2 d^2}\\ &=-\frac {a^2 \left (2 A (c-2 d) d-B \left (2 c^2-4 c d+3 d^2\right )\right ) x}{2 d^3}+\frac {a^2 (2 B c-2 A d-3 B d) \cos (e+f x)}{2 d^2 f}-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f}-\frac {\left (a^2 (c-d)^2 (B c-A d)\right ) \int \frac {1}{c+d \sin (e+f x)} \, dx}{d^3}\\ &=-\frac {a^2 \left (2 A (c-2 d) d-B \left (2 c^2-4 c d+3 d^2\right )\right ) x}{2 d^3}+\frac {a^2 (2 B c-2 A d-3 B d) \cos (e+f x)}{2 d^2 f}-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f}-\frac {\left (2 a^2 (c-d)^2 (B c-A d)\right ) \text {Subst}\left (\int \frac {1}{c+2 d x+c x^2} \, dx,x,\tan \left (\frac {1}{2} (e+f x)\right )\right )}{d^3 f}\\ &=-\frac {a^2 \left (2 A (c-2 d) d-B \left (2 c^2-4 c d+3 d^2\right )\right ) x}{2 d^3}+\frac {a^2 (2 B c-2 A d-3 B d) \cos (e+f x)}{2 d^2 f}-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f}+\frac {\left (4 a^2 (c-d)^2 (B c-A d)\right ) \text {Subst}\left (\int \frac {1}{-4 \left (c^2-d^2\right )-x^2} \, dx,x,2 d+2 c \tan \left (\frac {1}{2} (e+f x)\right )\right )}{d^3 f}\\ &=-\frac {a^2 \left (2 A (c-2 d) d-B \left (2 c^2-4 c d+3 d^2\right )\right ) x}{2 d^3}-\frac {2 a^2 (c-d)^2 (B c-A d) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{d^3 \sqrt {c^2-d^2} f}+\frac {a^2 (2 B c-2 A d-3 B d) \cos (e+f x)}{2 d^2 f}-\frac {B \cos (e+f x) \left (a^2+a^2 \sin (e+f x)\right )}{2 d f}\\ \end {align*}
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Mathematica [A]
time = 0.44, size = 177, normalized size = 1.04 \begin {gather*} \frac {a^2 (1+\sin (e+f x))^2 \left (2 \left (2 A d (-c+2 d)+B \left (2 c^2-4 c d+3 d^2\right )\right ) (e+f x)-\frac {8 (c-d)^2 (B c-A d) \tan ^{-1}\left (\frac {d+c \tan \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c^2-d^2}}\right )}{\sqrt {c^2-d^2}}-4 d (-B c+A d+2 B d) \cos (e+f x)-B d^2 \sin (2 (e+f x))\right )}{4 d^3 f \left (\cos \left (\frac {1}{2} (e+f x)\right )+\sin \left (\frac {1}{2} (e+f x)\right )\right )^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.36, size = 235, normalized size = 1.37
method | result | size |
derivativedivides | \(\frac {2 a^{2} \left (\frac {\left (A \,c^{2} d -2 A c \,d^{2}+A \,d^{3}-B \,c^{3}+2 B \,c^{2} d -B c \,d^{2}\right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{d^{3} \sqrt {c^{2}-d^{2}}}-\frac {\frac {-\frac {B \,d^{2} \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}+\left (A \,d^{2}-B c d +2 B \,d^{2}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\frac {B \,d^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{2}+A \,d^{2}-B c d +2 B \,d^{2}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{2}}+\frac {\left (2 A c d -4 A \,d^{2}-2 B \,c^{2}+4 B c d -3 B \,d^{2}\right ) \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}}{d^{3}}\right )}{f}\) | \(235\) |
default | \(\frac {2 a^{2} \left (\frac {\left (A \,c^{2} d -2 A c \,d^{2}+A \,d^{3}-B \,c^{3}+2 B \,c^{2} d -B c \,d^{2}\right ) \arctan \left (\frac {2 c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )+2 d}{2 \sqrt {c^{2}-d^{2}}}\right )}{d^{3} \sqrt {c^{2}-d^{2}}}-\frac {\frac {-\frac {B \,d^{2} \left (\tan ^{3}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}+\left (A \,d^{2}-B c d +2 B \,d^{2}\right ) \left (\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )+\frac {B \,d^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{2}+A \,d^{2}-B c d +2 B \,d^{2}}{\left (1+\tan ^{2}\left (\frac {f x}{2}+\frac {e}{2}\right )\right )^{2}}+\frac {\left (2 A c d -4 A \,d^{2}-2 B \,c^{2}+4 B c d -3 B \,d^{2}\right ) \arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}}{d^{3}}\right )}{f}\) | \(235\) |
risch | \(-\frac {a^{2} x A c}{d^{2}}+\frac {2 a^{2} x A}{d}+\frac {a^{2} x B \,c^{2}}{d^{3}}-\frac {2 a^{2} x B c}{d^{2}}+\frac {3 a^{2} x B}{2 d}-\frac {a^{2} {\mathrm e}^{i \left (f x +e \right )} A}{2 d f}+\frac {a^{2} {\mathrm e}^{i \left (f x +e \right )} B c}{2 d^{2} f}-\frac {a^{2} {\mathrm e}^{i \left (f x +e \right )} B}{d f}-\frac {a^{2} {\mathrm e}^{-i \left (f x +e \right )} A}{2 d f}+\frac {a^{2} {\mathrm e}^{-i \left (f x +e \right )} B c}{2 d^{2} f}-\frac {a^{2} {\mathrm e}^{-i \left (f x +e \right )} B}{d f}+\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c +\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) A c}{\left (c +d \right ) f \,d^{2}}-\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c +\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) A}{\left (c +d \right ) f d}-\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c +\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) B \,c^{2}}{\left (c +d \right ) f \,d^{3}}+\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c +\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) B c}{\left (c +d \right ) f \,d^{2}}-\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c -\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) A c}{\left (c +d \right ) f \,d^{2}}+\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c -\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) A}{\left (c +d \right ) f d}+\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c -\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) B \,c^{2}}{\left (c +d \right ) f \,d^{3}}-\frac {\sqrt {-\left (c -d \right ) \left (c +d \right )}\, a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+\frac {i c -\sqrt {-\left (c -d \right ) \left (c +d \right )}}{d}\right ) B c}{\left (c +d \right ) f \,d^{2}}-\frac {B \,a^{2} \sin \left (2 f x +2 e \right )}{4 d f}\) | \(707\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.48, size = 467, normalized size = 2.73 \begin {gather*} \left [-\frac {B a^{2} d^{2} \cos \left (f x + e\right ) \sin \left (f x + e\right ) - {\left (2 \, B a^{2} c^{2} - 2 \, {\left (A + 2 \, B\right )} a^{2} c d + {\left (4 \, A + 3 \, B\right )} a^{2} d^{2}\right )} f x + {\left (B a^{2} c^{2} - {\left (A + B\right )} a^{2} c d + A a^{2} d^{2}\right )} \sqrt {-\frac {c - d}{c + d}} \log \left (-\frac {{\left (2 \, c^{2} - d^{2}\right )} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2} - 2 \, {\left ({\left (c^{2} + c d\right )} \cos \left (f x + e\right ) \sin \left (f x + e\right ) + {\left (c d + d^{2}\right )} \cos \left (f x + e\right )\right )} \sqrt {-\frac {c - d}{c + d}}}{d^{2} \cos \left (f x + e\right )^{2} - 2 \, c d \sin \left (f x + e\right ) - c^{2} - d^{2}}\right ) - 2 \, {\left (B a^{2} c d - {\left (A + 2 \, B\right )} a^{2} d^{2}\right )} \cos \left (f x + e\right )}{2 \, d^{3} f}, -\frac {B a^{2} d^{2} \cos \left (f x + e\right ) \sin \left (f x + e\right ) - {\left (2 \, B a^{2} c^{2} - 2 \, {\left (A + 2 \, B\right )} a^{2} c d + {\left (4 \, A + 3 \, B\right )} a^{2} d^{2}\right )} f x - 2 \, {\left (B a^{2} c^{2} - {\left (A + B\right )} a^{2} c d + A a^{2} d^{2}\right )} \sqrt {\frac {c - d}{c + d}} \arctan \left (-\frac {{\left (c \sin \left (f x + e\right ) + d\right )} \sqrt {\frac {c - d}{c + d}}}{{\left (c - d\right )} \cos \left (f x + e\right )}\right ) - 2 \, {\left (B a^{2} c d - {\left (A + 2 \, B\right )} a^{2} d^{2}\right )} \cos \left (f x + e\right )}{2 \, d^{3} f}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.59, size = 314, normalized size = 1.84 \begin {gather*} \frac {\frac {{\left (2 \, B a^{2} c^{2} - 2 \, A a^{2} c d - 4 \, B a^{2} c d + 4 \, A a^{2} d^{2} + 3 \, B a^{2} d^{2}\right )} {\left (f x + e\right )}}{d^{3}} - \frac {4 \, {\left (B a^{2} c^{3} - A a^{2} c^{2} d - 2 \, B a^{2} c^{2} d + 2 \, A a^{2} c d^{2} + B a^{2} c d^{2} - A a^{2} d^{3}\right )} {\left (\pi \left \lfloor \frac {f x + e}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (c\right ) + \arctan \left (\frac {c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + d}{\sqrt {c^{2} - d^{2}}}\right )\right )}}{\sqrt {c^{2} - d^{2}} d^{3}} + \frac {2 \, {\left (B a^{2} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 2 \, B a^{2} c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 2 \, A a^{2} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - 4 \, B a^{2} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} - B a^{2} d \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 2 \, B a^{2} c - 2 \, A a^{2} d - 4 \, B a^{2} d\right )}}{{\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 1\right )}^{2} d^{2}}}{2 \, f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 20.07, size = 2500, normalized size = 14.62 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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